3.191 \(\int \frac {\tan (x)}{\sec (x)+\tan (x)} \, dx\)

Optimal. Leaf size=11 \[ x+\frac {\cos (x)}{\sin (x)+1} \]

[Out]

x+cos(x)/(1+sin(x))

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Rubi [A]  time = 0.05, antiderivative size = 11, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.300, Rules used = {4391, 2735, 2648} \[ x+\frac {\cos (x)}{\sin (x)+1} \]

Antiderivative was successfully verified.

[In]

Int[Tan[x]/(Sec[x] + Tan[x]),x]

[Out]

x + Cos[x]/(1 + Sin[x])

Rule 2648

Int[((a_) + (b_.)*sin[(c_.) + (d_.)*(x_)])^(-1), x_Symbol] :> -Simp[Cos[c + d*x]/(d*(b + a*Sin[c + d*x])), x]
/; FreeQ[{a, b, c, d}, x] && EqQ[a^2 - b^2, 0]

Rule 2735

Int[((a_.) + (b_.)*sin[(e_.) + (f_.)*(x_)])/((c_.) + (d_.)*sin[(e_.) + (f_.)*(x_)]), x_Symbol] :> Simp[(b*x)/d
, x] - Dist[(b*c - a*d)/d, Int[1/(c + d*Sin[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && NeQ[b*c - a*d
, 0]

Rule 4391

Int[(u_.)*((b_.)*sec[(c_.) + (d_.)*(x_)]^(n_.) + (a_.)*tan[(c_.) + (d_.)*(x_)]^(n_.))^(p_), x_Symbol] :> Int[A
ctivateTrig[u]*Sec[c + d*x]^(n*p)*(b + a*Sin[c + d*x]^n)^p, x] /; FreeQ[{a, b, c, d}, x] && IntegersQ[n, p]

Rubi steps

\begin {align*} \int \frac {\tan (x)}{\sec (x)+\tan (x)} \, dx &=\int \frac {\sin (x)}{1+\sin (x)} \, dx\\ &=x-\int \frac {1}{1+\sin (x)} \, dx\\ &=x+\frac {\cos (x)}{1+\sin (x)}\\ \end {align*}

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Mathematica [B]  time = 0.03, size = 25, normalized size = 2.27 \[ x-\frac {2 \sin \left (\frac {x}{2}\right )}{\sin \left (\frac {x}{2}\right )+\cos \left (\frac {x}{2}\right )} \]

Antiderivative was successfully verified.

[In]

Integrate[Tan[x]/(Sec[x] + Tan[x]),x]

[Out]

x - (2*Sin[x/2])/(Cos[x/2] + Sin[x/2])

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fricas [B]  time = 0.70, size = 24, normalized size = 2.18 \[ \frac {{\left (x + 1\right )} \cos \relax (x) + {\left (x - 1\right )} \sin \relax (x) + x + 1}{\cos \relax (x) + \sin \relax (x) + 1} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tan(x)/(sec(x)+tan(x)),x, algorithm="fricas")

[Out]

((x + 1)*cos(x) + (x - 1)*sin(x) + x + 1)/(cos(x) + sin(x) + 1)

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giac [A]  time = 0.96, size = 12, normalized size = 1.09 \[ x + \frac {2}{\tan \left (\frac {1}{2} \, x\right ) + 1} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tan(x)/(sec(x)+tan(x)),x, algorithm="giac")

[Out]

x + 2/(tan(1/2*x) + 1)

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maple [A]  time = 0.08, size = 13, normalized size = 1.18 \[ \frac {2}{\tan \left (\frac {x}{2}\right )+1}+x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(tan(x)/(sec(x)+tan(x)),x)

[Out]

2/(tan(1/2*x)+1)+x

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maxima [B]  time = 0.43, size = 28, normalized size = 2.55 \[ \frac {2}{\frac {\sin \relax (x)}{\cos \relax (x) + 1} + 1} + 2 \, \arctan \left (\frac {\sin \relax (x)}{\cos \relax (x) + 1}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tan(x)/(sec(x)+tan(x)),x, algorithm="maxima")

[Out]

2/(sin(x)/(cos(x) + 1) + 1) + 2*arctan(sin(x)/(cos(x) + 1))

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mupad [B]  time = 0.58, size = 12, normalized size = 1.09 \[ x+\frac {2}{\mathrm {tan}\left (\frac {x}{2}\right )+1} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(tan(x)/(tan(x) + 1/cos(x)),x)

[Out]

x + 2/(tan(x/2) + 1)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\tan {\relax (x )}}{\tan {\relax (x )} + \sec {\relax (x )}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tan(x)/(sec(x)+tan(x)),x)

[Out]

Integral(tan(x)/(tan(x) + sec(x)), x)

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